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50113121142121 is a prime number
BaseRepresentation
bin10110110010011110111101…
…10010001100010101101001
320120102202201120112200121021
423121033132302030111221
523032023133003021441
6254325352224012441
713361360600313232
oct1331173662142551
9216382646480537
1050113121142121
1114a709454904a4
125754312a61121
1321c685473b12b
14c536b912a089
155bd855c7a3d1
hex2d93dec8c569

50113121142121 has 2 divisors, whose sum is σ = 50113121142122. Its totient is φ = 50113121142120.

The previous prime is 50113121142031. The next prime is 50113121142127. The reversal of 50113121142121 is 12124112131105.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 39160198511721 + 10952922630400 = 6257811^2 + 3309520^2 .

It is a cyclic number.

It is not a de Polignac number, because 50113121142121 - 211 = 50113121140073 is a prime.

It is a super-2 number, since 2×501131211421212 (a number of 28 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (50113121142127) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25056560571060 + 25056560571061.

It is an arithmetic number, because the mean of its divisors is an integer number (25056560571061).

Almost surely, 250113121142121 is an apocalyptic number.

It is an amenable number.

50113121142121 is a deficient number, since it is larger than the sum of its proper divisors (1).

50113121142121 is an equidigital number, since it uses as much as digits as its factorization.

50113121142121 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 480, while the sum is 25.

Adding to 50113121142121 its reverse (12124112131105), we get a palindrome (62237233273226).

The spelling of 50113121142121 in words is "fifty trillion, one hundred thirteen billion, one hundred twenty-one million, one hundred forty-two thousand, one hundred twenty-one".