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501133506131 = 3971262301023
BaseRepresentation
bin1110100101011011110…
…00100111011001010011
31202220111212002210100002
413102231320213121103
531202310134144011
61022114554120215
751130361343056
oct7225570473123
91686455083302
10501133506131
11183590888425
128115872006b
1338344c3056b
141a37d9a4a9d
15d0803d6c3b
hex74ade27653

501133506131 has 4 divisors (see below), whose sum is σ = 502395807552. Its totient is φ = 499871204712.

The previous prime is 501133506127. The next prime is 501133506179. The reversal of 501133506131 is 131605331105.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 501133506131 - 22 = 501133506127 is a prime.

It is a super-2 number, since 2×5011335061312 (a number of 24 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 501133506094 and 501133506103.

It is not an unprimeable number, because it can be changed into a prime (501133506121) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 631150115 + ... + 631150908.

It is an arithmetic number, because the mean of its divisors is an integer number (125598951888).

Almost surely, 2501133506131 is an apocalyptic number.

501133506131 is a deficient number, since it is larger than the sum of its proper divisors (1262301421).

501133506131 is a wasteful number, since it uses less digits than its factorization.

501133506131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1262301420.

The product of its (nonzero) digits is 4050, while the sum is 29.

Adding to 501133506131 its reverse (131605331105), we get a palindrome (632738837236).

The spelling of 501133506131 in words is "five hundred one billion, one hundred thirty-three million, five hundred six thousand, one hundred thirty-one".

Divisors: 1 397 1262301023 501133506131