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5011553537 is a prime number
BaseRepresentation
bin1001010101011011…
…00011110100000001
3110221021010022000222
410222231203310001
540230424203122
62145142552425
7235122334154
oct45255436401
913837108028
105011553537
112141989391
12b7a438715
1361b3755c3
1435782bc9b
151e4e89b42
hex12ab63d01

5011553537 has 2 divisors, whose sum is σ = 5011553538. Its totient is φ = 5011553536.

The previous prime is 5011553479. The next prime is 5011553579. The reversal of 5011553537 is 7353551105.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4096128001 + 915425536 = 64001^2 + 30256^2 .

It is a cyclic number.

It is not a de Polignac number, because 5011553537 - 26 = 5011553473 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 5011553497 and 5011553506.

It is not a weakly prime, because it can be changed into another prime (5011553137) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2505776768 + 2505776769.

It is an arithmetic number, because the mean of its divisors is an integer number (2505776769).

Almost surely, 25011553537 is an apocalyptic number.

It is an amenable number.

5011553537 is a deficient number, since it is larger than the sum of its proper divisors (1).

5011553537 is an equidigital number, since it uses as much as digits as its factorization.

5011553537 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 39375, while the sum is 35.

The square root of 5011553537 is about 70792.3268228980. The cubic root of 5011553537 is about 1711.2920182025.

The spelling of 5011553537 in words is "five billion, eleven million, five hundred fifty-three thousand, five hundred thirty-seven".