Base | Representation |
---|---|
bin | 101110101011001101… |
… | …010100000100101011 |
3 | 11210100202001010110221 |
4 | 232223031110010223 |
5 | 1310114430044113 |
6 | 35005021550511 |
7 | 3422642522401 |
oct | 565315240453 |
9 | 153322033427 |
10 | 50117034283 |
11 | 1a2888396a8 |
12 | 9868115437 |
13 | 4959098a94 |
14 | 25d60b7471 |
15 | 1484cb198d |
hex | bab35412b |
50117034283 has 2 divisors, whose sum is σ = 50117034284. Its totient is φ = 50117034282.
The previous prime is 50117034241. The next prime is 50117034299. The reversal of 50117034283 is 38243071105.
50117034283 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-50117034283 is a prime.
It is not a weakly prime, because it can be changed into another prime (50117034083) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25058517141 + 25058517142.
It is an arithmetic number, because the mean of its divisors is an integer number (25058517142).
Almost surely, 250117034283 is an apocalyptic number.
50117034283 is a deficient number, since it is larger than the sum of its proper divisors (1).
50117034283 is an equidigital number, since it uses as much as digits as its factorization.
50117034283 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 20160, while the sum is 34.
The spelling of 50117034283 in words is "fifty billion, one hundred seventeen million, thirty-four thousand, two hundred eighty-three".
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