Base | Representation |
---|---|
bin | 10110110010100110100111… |
… | …01000011101001001010001 |
3 | 20120110011022212012212110021 |
4 | 23121103103220131021101 |
5 | 23032110041111214231 |
6 | 254331312005503441 |
7 | 13361564440511041 |
oct | 1331232350351121 |
9 | 216404285185407 |
10 | 50117229007441 |
11 | 14a72663248512 |
12 | 575507a711b81 |
13 | 21c705a7c837b |
14 | c5398891b721 |
15 | 5bd9e670a811 |
hex | 2d94d3a1d251 |
50117229007441 has 2 divisors, whose sum is σ = 50117229007442. Its totient is φ = 50117229007440.
The previous prime is 50117229007427. The next prime is 50117229007519. The reversal of 50117229007441 is 14470092271105.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 49284317237841 + 832911769600 = 7020279^2 + 912640^2 .
It is a cyclic number.
It is not a de Polignac number, because 50117229007441 - 225 = 50117195453009 is a prime.
It is not a weakly prime, because it can be changed into another prime (50117229017441) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25058614503720 + 25058614503721.
It is an arithmetic number, because the mean of its divisors is an integer number (25058614503721).
Almost surely, 250117229007441 is an apocalyptic number.
It is an amenable number.
50117229007441 is a deficient number, since it is larger than the sum of its proper divisors (1).
50117229007441 is an equidigital number, since it uses as much as digits as its factorization.
50117229007441 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 141120, while the sum is 43.
The spelling of 50117229007441 in words is "fifty trillion, one hundred seventeen billion, two hundred twenty-nine million, seven thousand, four hundred forty-one".
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