5012049433 has 2 divisors, whose sum is σ = 5012049434. Its totient is φ = 5012049432.

The previous prime is 5012049421. The next prime is 5012049437. The reversal of 5012049433 is 3349402105.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4477884889 + 534164544 = 66917^2 + 23112^2 .

It is a cyclic number.

It is not a de Polignac number, because 5012049433 - 2⁵ = 5012049401 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 5012049395 and 5012049404.

It is not a weakly prime, because it can be changed into another prime (5012049437) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2506024716 + 2506024717.

It is an arithmetic number, because the mean of its divisors is an integer number (2506024717).

Almost surely, 2^5012049433 is an apocalyptic number.

It is an amenable number.

5012049433 is a deficient number, since it is larger than the sum of its proper divisors (1).

5012049433 is an equidigital number, since it uses as much as digits as its factorization.

5012049433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12960, while the sum is 31.

The square root of 5012049433 is about 70795.8292062463. The cubic root of 5012049433 is about 1711.3484607721.

The spelling of 5012049433 in words is "five billion, twelve million, forty-nine thousand, four hundred thirty-three".