Base | Representation |
---|---|
bin | 111000111110111100100100… |
… | …1110101111000100110101001 |
3 | 2102201201100201120210200020112 |
4 | 1301331321021311320212221 |
5 | 1011144143141113140131 |
6 | 4534011012020304105 |
7 | 210401565625224521 |
oct | 16175711165704651 |
9 | 2381640646720215 |
10 | 501232512240041 |
11 | 13578757306702a |
12 | 48272276242035 |
13 | 1868b03b96a24a |
14 | 8babad6908681 |
15 | 3ce331ba5a02b |
hex | 1c7de49d789a9 |
501232512240041 has 2 divisors, whose sum is σ = 501232512240042. Its totient is φ = 501232512240040.
The previous prime is 501232512240037. The next prime is 501232512240127. The reversal of 501232512240041 is 140042215232105.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 360377866271641 + 140854645968400 = 18983621^2 + 11868220^2 .
It is a cyclic number.
It is not a de Polignac number, because 501232512240041 - 22 = 501232512240037 is a prime.
It is not a weakly prime, because it can be changed into another prime (501232512240541) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 250616256120020 + 250616256120021.
It is an arithmetic number, because the mean of its divisors is an integer number (250616256120021).
Almost surely, 2501232512240041 is an apocalyptic number.
It is an amenable number.
501232512240041 is a deficient number, since it is larger than the sum of its proper divisors (1).
501232512240041 is an equidigital number, since it uses as much as digits as its factorization.
501232512240041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 19200, while the sum is 32.
Adding to 501232512240041 its reverse (140042215232105), we get a palindrome (641274727472146).
The spelling of 501232512240041 in words is "five hundred one trillion, two hundred thirty-two billion, five hundred twelve million, two hundred forty thousand, forty-one".
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