Base | Representation |
---|---|
bin | 10110110010110100010110… |
… | …00010110011101000110001 |
3 | 20120110212100122010122021222 |
4 | 23121122023002303220301 |
5 | 23032220140341110022 |
6 | 254334531315354425 |
7 | 13362245225413415 |
oct | 1331321302635061 |
9 | 216425318118258 |
10 | 50124601113137 |
11 | 14a757a6645651 |
12 | 57565975b2a15 |
13 | 21c7963c271a5 |
14 | c54087a5ad45 |
15 | 5bdcc8a28242 |
hex | 2d968b0b3a31 |
50124601113137 has 2 divisors, whose sum is σ = 50124601113138. Its totient is φ = 50124601113136.
The previous prime is 50124601113121. The next prime is 50124601113157. The reversal of 50124601113137 is 73131110642105.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 41774298596416 + 8350302516721 = 6463304^2 + 2889689^2 .
It is a cyclic number.
It is not a de Polignac number, because 50124601113137 - 24 = 50124601113121 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 50124601113097 and 50124601113106.
It is not a weakly prime, because it can be changed into another prime (50124601113157) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25062300556568 + 25062300556569.
It is an arithmetic number, because the mean of its divisors is an integer number (25062300556569).
Almost surely, 250124601113137 is an apocalyptic number.
It is an amenable number.
50124601113137 is a deficient number, since it is larger than the sum of its proper divisors (1).
50124601113137 is an equidigital number, since it uses as much as digits as its factorization.
50124601113137 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15120, while the sum is 35.
The spelling of 50124601113137 in words is "fifty trillion, one hundred twenty-four billion, six hundred one million, one hundred thirteen thousand, one hundred thirty-seven".
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