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50134202233 = 140113578203
BaseRepresentation
bin101110101100001110…
…110011011101111001
311210101221100100110221
4232230032303131321
51310133323432413
635010433540041
73423241454623
oct565416633571
9153357310427
1050134202233
111a2974a5195
129871a14621
13495c7ca12b
1425d84a5c13
15148655368d
hexbac3b3779

50134202233 has 4 divisors (see below), whose sum is σ = 50137794448. Its totient is φ = 50130610020.

The previous prime is 50134202207. The next prime is 50134202249. The reversal of 50134202233 is 33220243105.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 50134202233 - 25 = 50134202201 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 50134202198 and 50134202207.

It is not an unprimeable number, because it can be changed into a prime (50134202203) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1775091 + ... + 1803112.

It is an arithmetic number, because the mean of its divisors is an integer number (12534448612).

Almost surely, 250134202233 is an apocalyptic number.

It is an amenable number.

50134202233 is a deficient number, since it is larger than the sum of its proper divisors (3592215).

50134202233 is a wasteful number, since it uses less digits than its factorization.

50134202233 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3592214.

The product of its (nonzero) digits is 4320, while the sum is 25.

Adding to 50134202233 its reverse (33220243105), we get a palindrome (83354445338).

The spelling of 50134202233 in words is "fifty billion, one hundred thirty-four million, two hundred two thousand, two hundred thirty-three".

Divisors: 1 14011 3578203 50134202233