Search a number
-
+
50136897393161 is a prime number
BaseRepresentation
bin10110110011001011001111…
…11101011001001000001001
320120112001002120202101102122
423121211213331121020021
523032420331213040121
6254344323411341025
713363162025154335
oct1331454775311011
9216461076671378
1050136897393161
1114a7aa3656a847
125758a495b1775
1321c8b73586527
14c548d2b607c5
155be2982c05ab
hex2d9967f59209

50136897393161 has 2 divisors, whose sum is σ = 50136897393162. Its totient is φ = 50136897393160.

The previous prime is 50136897393059. The next prime is 50136897393179. The reversal of 50136897393161 is 16139379863105.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 45630957194761 + 4505940198400 = 6755069^2 + 2122720^2 .

It is a cyclic number.

It is not a de Polignac number, because 50136897393161 - 230 = 50135823651337 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 50136897393094 and 50136897393103.

It is not a weakly prime, because it can be changed into another prime (50136897393761) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25068448696580 + 25068448696581.

It is an arithmetic number, because the mean of its divisors is an integer number (25068448696581).

Almost surely, 250136897393161 is an apocalyptic number.

It is an amenable number.

50136897393161 is a deficient number, since it is larger than the sum of its proper divisors (1).

50136897393161 is an equidigital number, since it uses as much as digits as its factorization.

50136897393161 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 22044960, while the sum is 62.

The spelling of 50136897393161 in words is "fifty trillion, one hundred thirty-six billion, eight hundred ninety-seven million, three hundred ninety-three thousand, one hundred sixty-one".