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5014025603753 = 5031199660623
BaseRepresentation
bin100100011110110101100…
…1101110000101010101001
3122202100002001202121201212
41020331223031300222221
51124122211023310003
614355224521522505
71025152141266155
oct110755315605251
918670061677655
105014025603753
111663488813221
1268b903043435
132a4a88a9909a
14134974406065
158a65dc10dd8
hex48f6b370aa9

5014025603753 has 4 divisors (see below), whose sum is σ = 5014125314688. Its totient is φ = 5013925892820.

The previous prime is 5014025603737. The next prime is 5014025603767. The reversal of 5014025603753 is 3573065204105.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 5014025603753 - 24 = 5014025603737 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 5014025603753.

It is not an unprimeable number, because it can be changed into a prime (5014025603053) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 49780001 + ... + 49880622.

It is an arithmetic number, because the mean of its divisors is an integer number (1253531328672).

Almost surely, 25014025603753 is an apocalyptic number.

It is an amenable number.

5014025603753 is a deficient number, since it is larger than the sum of its proper divisors (99710935).

5014025603753 is an equidigital number, since it uses as much as digits as its factorization.

5014025603753 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 99710934.

The product of its (nonzero) digits is 378000, while the sum is 41.

The spelling of 5014025603753 in words is "five trillion, fourteen billion, twenty-five million, six hundred three thousand, seven hundred fifty-three".

Divisors: 1 50311 99660623 5014025603753