Base | Representation |
---|---|
bin | 100100011110110101100… |
… | …1101110000101010101001 |
3 | 122202100002001202121201212 |
4 | 1020331223031300222221 |
5 | 1124122211023310003 |
6 | 14355224521522505 |
7 | 1025152141266155 |
oct | 110755315605251 |
9 | 18670061677655 |
10 | 5014025603753 |
11 | 1663488813221 |
12 | 68b903043435 |
13 | 2a4a88a9909a |
14 | 134974406065 |
15 | 8a65dc10dd8 |
hex | 48f6b370aa9 |
5014025603753 has 4 divisors (see below), whose sum is σ = 5014125314688. Its totient is φ = 5013925892820.
The previous prime is 5014025603737. The next prime is 5014025603767. The reversal of 5014025603753 is 3573065204105.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 5014025603753 - 24 = 5014025603737 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 5014025603753.
It is not an unprimeable number, because it can be changed into a prime (5014025603053) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 49780001 + ... + 49880622.
It is an arithmetic number, because the mean of its divisors is an integer number (1253531328672).
Almost surely, 25014025603753 is an apocalyptic number.
It is an amenable number.
5014025603753 is a deficient number, since it is larger than the sum of its proper divisors (99710935).
5014025603753 is an equidigital number, since it uses as much as digits as its factorization.
5014025603753 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 99710934.
The product of its (nonzero) digits is 378000, while the sum is 41.
The spelling of 5014025603753 in words is "five trillion, fourteen billion, twenty-five million, six hundred three thousand, seven hundred fifty-three".
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