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50141530043083 is a prime number
BaseRepresentation
bin10110110011010011111000…
…00101100011001011001011
320120112111001102220101102101
423121221330011203023023
523033004323142334313
6254350411221214231
713363414600063333
oct1331517405431313
9216474042811371
1050141530043083
1114a819a3582246
125759920b61377
1321c94312959bb
14c54c1211a0c3
155be469d625dd
hex2d9a7c1632cb

50141530043083 has 2 divisors, whose sum is σ = 50141530043084. Its totient is φ = 50141530043082.

The previous prime is 50141530043047. The next prime is 50141530043093. The reversal of 50141530043083 is 38034003514105.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 50141530043083 - 221 = 50141527945931 is a prime.

It is a super-2 number, since 2×501415300430832 (a number of 28 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (50141530043093) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25070765021541 + 25070765021542.

It is an arithmetic number, because the mean of its divisors is an integer number (25070765021542).

Almost surely, 250141530043083 is an apocalyptic number.

50141530043083 is a deficient number, since it is larger than the sum of its proper divisors (1).

50141530043083 is an equidigital number, since it uses as much as digits as its factorization.

50141530043083 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 86400, while the sum is 37.

Adding to 50141530043083 its reverse (38034003514105), we get a palindrome (88175533557188).

The spelling of 50141530043083 in words is "fifty trillion, one hundred forty-one billion, five hundred thirty million, forty-three thousand, eighty-three".