Base | Representation |
---|---|
bin | 111001000000010100110111… |
… | …1111110100111011001011011 |
3 | 2102202101111011102020121221111 |
4 | 1302000221233332213121123 |
5 | 1011210300010414432331 |
6 | 4534234051412321151 |
7 | 210421360556003605 |
oct | 16200515776473133 |
9 | 2382344142217844 |
10 | 501422130624091 |
11 | 13584aa27764536 |
12 | 482a2b750131b7 |
13 | 186a2b9a1c63b1 |
14 | 8bb6d63cca175 |
15 | 3ce821888edb1 |
hex | 1c80a6ffa765b |
501422130624091 has 2 divisors, whose sum is σ = 501422130624092. Its totient is φ = 501422130624090.
The previous prime is 501422130623987. The next prime is 501422130624133. The reversal of 501422130624091 is 190426031224105.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 501422130624091 - 231 = 501419983140443 is a prime.
It is not a weakly prime, because it can be changed into another prime (501422130624991) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 250711065312045 + 250711065312046.
It is an arithmetic number, because the mean of its divisors is an integer number (250711065312046).
Almost surely, 2501422130624091 is an apocalyptic number.
501422130624091 is a deficient number, since it is larger than the sum of its proper divisors (1).
501422130624091 is an equidigital number, since it uses as much as digits as its factorization.
501422130624091 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 103680, while the sum is 40.
Adding to 501422130624091 its reverse (190426031224105), we get a palindrome (691848161848196).
The spelling of 501422130624091 in words is "five hundred one trillion, four hundred twenty-two billion, one hundred thirty million, six hundred twenty-four thousand, ninety-one".
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