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5014221451331 is a prime number
BaseRepresentation
bin100100011110111011011…
…1000110111000001000011
3122202100120201021201002212
41020331312320313001003
51124123111142420311
614355300155332335
71025160040050311
oct110756670670103
918670521251085
105014221451331
11166357931a424
1268b9587510ab
132a4aba52b321
141349924270b1
158a670ee9c8b
hex48f76e37043

5014221451331 has 2 divisors, whose sum is σ = 5014221451332. Its totient is φ = 5014221451330.

The previous prime is 5014221451273. The next prime is 5014221451367. The reversal of 5014221451331 is 1331541224105.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-5014221451331 is a prime.

It is a super-2 number, since 2×50142214513312 (a number of 26 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (5014221457331) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2507110725665 + 2507110725666.

It is an arithmetic number, because the mean of its divisors is an integer number (2507110725666).

Almost surely, 25014221451331 is an apocalyptic number.

5014221451331 is a deficient number, since it is larger than the sum of its proper divisors (1).

5014221451331 is an equidigital number, since it uses as much as digits as its factorization.

5014221451331 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 14400, while the sum is 32.

Adding to 5014221451331 its reverse (1331541224105), we get a palindrome (6345762675436).

The spelling of 5014221451331 in words is "five trillion, fourteen billion, two hundred twenty-one million, four hundred fifty-one thousand, three hundred thirty-one".