Base | Representation |
---|---|
bin | 100100011111011011111… |
… | …1010100010101101111001 |
3 | 122202110101202010020010112 |
4 | 1020332313322202231321 |
5 | 1124132324434132023 |
6 | 14400000330354105 |
7 | 1025226055053245 |
oct | 110766772425571 |
9 | 18673352106115 |
10 | 5015312411513 |
11 | 1663a8911aa08 |
12 | 690001b8b935 |
13 | 2a4c325654b1 |
14 | 134a57291425 |
15 | 8a6d6b97478 |
hex | 48fb7ea2b79 |
5015312411513 has 2 divisors, whose sum is σ = 5015312411514. Its totient is φ = 5015312411512.
The previous prime is 5015312411419. The next prime is 5015312411521. The reversal of 5015312411513 is 3151142135105.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 4417214348089 + 598098063424 = 2101717^2 + 773368^2 .
It is a cyclic number.
It is not a de Polignac number, because 5015312411513 - 210 = 5015312410489 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 5015312411513.
It is not a weakly prime, because it can be changed into another prime (5015312411113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2507656205756 + 2507656205757.
It is an arithmetic number, because the mean of its divisors is an integer number (2507656205757).
Almost surely, 25015312411513 is an apocalyptic number.
It is an amenable number.
5015312411513 is a deficient number, since it is larger than the sum of its proper divisors (1).
5015312411513 is an equidigital number, since it uses as much as digits as its factorization.
5015312411513 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9000, while the sum is 32.
Adding to 5015312411513 its reverse (3151142135105), we get a palindrome (8166454546618).
The spelling of 5015312411513 in words is "five trillion, fifteen billion, three hundred twelve million, four hundred eleven thousand, five hundred thirteen".
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