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5015312411513 is a prime number
BaseRepresentation
bin100100011111011011111…
…1010100010101101111001
3122202110101202010020010112
41020332313322202231321
51124132324434132023
614400000330354105
71025226055053245
oct110766772425571
918673352106115
105015312411513
111663a8911aa08
12690001b8b935
132a4c325654b1
14134a57291425
158a6d6b97478
hex48fb7ea2b79

5015312411513 has 2 divisors, whose sum is σ = 5015312411514. Its totient is φ = 5015312411512.

The previous prime is 5015312411419. The next prime is 5015312411521. The reversal of 5015312411513 is 3151142135105.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4417214348089 + 598098063424 = 2101717^2 + 773368^2 .

It is a cyclic number.

It is not a de Polignac number, because 5015312411513 - 210 = 5015312410489 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 5015312411513.

It is not a weakly prime, because it can be changed into another prime (5015312411113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2507656205756 + 2507656205757.

It is an arithmetic number, because the mean of its divisors is an integer number (2507656205757).

Almost surely, 25015312411513 is an apocalyptic number.

It is an amenable number.

5015312411513 is a deficient number, since it is larger than the sum of its proper divisors (1).

5015312411513 is an equidigital number, since it uses as much as digits as its factorization.

5015312411513 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 9000, while the sum is 32.

Adding to 5015312411513 its reverse (3151142135105), we get a palindrome (8166454546618).

The spelling of 5015312411513 in words is "five trillion, fifteen billion, three hundred twelve million, four hundred eleven thousand, five hundred thirteen".