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5015312441417 is a prime number
BaseRepresentation
bin100100011111011011111…
…1010101010000001001001
3122202110101202011202011002
41020332313322222001021
51124132324441111132
614400000331144345
71025226055236365
oct110766772520111
918673352152132
105015312441417
111663a89140423
12690001ba50b5
132a4c32575ca5
14134a5729c2a5
158a6d6ba1262
hex48fb7eaa049

5015312441417 has 2 divisors, whose sum is σ = 5015312441418. Its totient is φ = 5015312441416.

The previous prime is 5015312441371. The next prime is 5015312441441. The reversal of 5015312441417 is 7141442135105.

5015312441417 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 5005350205696 + 9962235721 = 2237264^2 + 99811^2 .

It is a cyclic number.

It is not a de Polignac number, because 5015312441417 - 224 = 5015295664201 is a prime.

It is not a weakly prime, because it can be changed into another prime (5015312441467) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2507656220708 + 2507656220709.

It is an arithmetic number, because the mean of its divisors is an integer number (2507656220709).

Almost surely, 25015312441417 is an apocalyptic number.

It is an amenable number.

5015312441417 is a deficient number, since it is larger than the sum of its proper divisors (1).

5015312441417 is an equidigital number, since it uses as much as digits as its factorization.

5015312441417 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 67200, while the sum is 38.

The spelling of 5015312441417 in words is "five trillion, fifteen billion, three hundred twelve million, four hundred forty-one thousand, four hundred seventeen".