Base | Representation |
---|---|
bin | 1001010101110111… |
… | …11001111001110001 |
3 | 110221112012100110121 |
4 | 10222323321321301 |
5 | 40232410022113 |
6 | 2145355330241 |
7 | 235166315542 |
oct | 45273717161 |
9 | 13845170417 |
10 | 5015314033 |
11 | 2144017734 |
12 | b7b750981 |
13 | 61c091152 |
14 | 35812a4c9 |
15 | 1e547de8d |
hex | 12aef9e71 |
5015314033 has 2 divisors, whose sum is σ = 5015314034. Its totient is φ = 5015314032.
The previous prime is 5015314001. The next prime is 5015314037. The reversal of 5015314033 is 3304135105.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2842169344 + 2173144689 = 53312^2 + 46617^2 .
It is a cyclic number.
It is not a de Polignac number, because 5015314033 - 25 = 5015314001 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5015313989 and 5015314007.
It is not a weakly prime, because it can be changed into another prime (5015314037) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2507657016 + 2507657017.
It is an arithmetic number, because the mean of its divisors is an integer number (2507657017).
Almost surely, 25015314033 is an apocalyptic number.
It is an amenable number.
5015314033 is a deficient number, since it is larger than the sum of its proper divisors (1).
5015314033 is an equidigital number, since it uses as much as digits as its factorization.
5015314033 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2700, while the sum is 25.
The square root of 5015314033 is about 70818.8818960028. The cubic root of 5015314033 is about 1711.7199425844.
Adding to 5015314033 its reverse (3304135105), we get a palindrome (8319449138).
The spelling of 5015314033 in words is "five billion, fifteen million, three hundred fourteen thousand, thirty-three".
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