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5015342030483 is a prime number
BaseRepresentation
bin100100011111011100110…
…1011100001111010010011
3122202110110210212000201102
41020332321223201322103
51124132410024433413
614400003305255015
71025226564604031
oct110767153417223
918673423760642
105015342030483
111663aa39100a4
1269000ba9446b
132a4c38735c05
14134a5b1a1551
158a6d9598458
hex48fb9ae1e93

5015342030483 has 2 divisors, whose sum is σ = 5015342030484. Its totient is φ = 5015342030482.

The previous prime is 5015342030443. The next prime is 5015342030549. The reversal of 5015342030483 is 3840302435105.

5015342030483 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 5015342030483 - 210 = 5015342029459 is a prime.

It is a Sophie Germain prime.

It is not a weakly prime, because it can be changed into another prime (5015342030443) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2507671015241 + 2507671015242.

It is an arithmetic number, because the mean of its divisors is an integer number (2507671015242).

Almost surely, 25015342030483 is an apocalyptic number.

5015342030483 is a deficient number, since it is larger than the sum of its proper divisors (1).

5015342030483 is an equidigital number, since it uses as much as digits as its factorization.

5015342030483 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 172800, while the sum is 38.

Adding to 5015342030483 its reverse (3840302435105), we get a palindrome (8855644465588).

The spelling of 5015342030483 in words is "five trillion, fifteen billion, three hundred forty-two million, thirty thousand, four hundred eighty-three".