Base | Representation |
---|---|
bin | 100100011111011100110… |
… | …1011100001111010010011 |
3 | 122202110110210212000201102 |
4 | 1020332321223201322103 |
5 | 1124132410024433413 |
6 | 14400003305255015 |
7 | 1025226564604031 |
oct | 110767153417223 |
9 | 18673423760642 |
10 | 5015342030483 |
11 | 1663aa39100a4 |
12 | 69000ba9446b |
13 | 2a4c38735c05 |
14 | 134a5b1a1551 |
15 | 8a6d9598458 |
hex | 48fb9ae1e93 |
5015342030483 has 2 divisors, whose sum is σ = 5015342030484. Its totient is φ = 5015342030482.
The previous prime is 5015342030443. The next prime is 5015342030549. The reversal of 5015342030483 is 3840302435105.
5015342030483 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5015342030483 - 210 = 5015342029459 is a prime.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (5015342030443) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2507671015241 + 2507671015242.
It is an arithmetic number, because the mean of its divisors is an integer number (2507671015242).
Almost surely, 25015342030483 is an apocalyptic number.
5015342030483 is a deficient number, since it is larger than the sum of its proper divisors (1).
5015342030483 is an equidigital number, since it uses as much as digits as its factorization.
5015342030483 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 172800, while the sum is 38.
Adding to 5015342030483 its reverse (3840302435105), we get a palindrome (8855644465588).
The spelling of 5015342030483 in words is "five trillion, fifteen billion, three hundred forty-two million, thirty thousand, four hundred eighty-three".
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