Base | Representation |
---|---|
bin | 10110110101000001011011… |
… | …00100001111010001001011 |
3 | 20120202002212011102001001211 |
4 | 23122200231210033101023 |
5 | 23034440300102330331 |
6 | 254433415134353551 |
7 | 13400566164321364 |
oct | 1332405544172113 |
9 | 216662764361054 |
10 | 50200342230091 |
11 | 14aa4933517879 |
12 | 57691b505b8b7 |
13 | 2201b44907861 |
14 | c579d0d32b6b |
15 | 5c0c5d1858b1 |
hex | 2da82d90f44b |
50200342230091 has 2 divisors, whose sum is σ = 50200342230092. Its totient is φ = 50200342230090.
The previous prime is 50200342230053. The next prime is 50200342230107. The reversal of 50200342230091 is 19003224300205.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-50200342230091 is a prime.
It is not a weakly prime, because it can be changed into another prime (50200342230011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25100171115045 + 25100171115046.
It is an arithmetic number, because the mean of its divisors is an integer number (25100171115046).
Almost surely, 250200342230091 is an apocalyptic number.
50200342230091 is a deficient number, since it is larger than the sum of its proper divisors (1).
50200342230091 is an equidigital number, since it uses as much as digits as its factorization.
50200342230091 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12960, while the sum is 31.
Adding to 50200342230091 its reverse (19003224300205), we get a palindrome (69203566530296).
The spelling of 50200342230091 in words is "fifty trillion, two hundred billion, three hundred forty-two million, two hundred thirty thousand, ninety-one".
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