Base | Representation |
---|---|
bin | 10110110101111001011110… |
… | …00101110100001101011001 |
3 | 20120211222112012201012211012 |
4 | 23122330233011310031121 |
5 | 23040433411220033231 |
6 | 254455313035143305 |
7 | 13403012642142341 |
oct | 1332745705641531 |
9 | 216758465635735 |
10 | 50230432580441 |
11 | 15006674761413 |
12 | 5772bb22a4b35 |
13 | 220492b9151a9 |
14 | c59247379d21 |
15 | 5c191eba9e2b |
hex | 2daf2f174359 |
50230432580441 has 2 divisors, whose sum is σ = 50230432580442. Its totient is φ = 50230432580440.
The previous prime is 50230432580389. The next prime is 50230432580467. The reversal of 50230432580441 is 14408523403205.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 50177332291216 + 53100289225 = 7083596^2 + 230435^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-50230432580441 is a prime.
It is not a weakly prime, because it can be changed into another prime (50230432580941) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25115216290220 + 25115216290221.
It is an arithmetic number, because the mean of its divisors is an integer number (25115216290221).
Almost surely, 250230432580441 is an apocalyptic number.
It is an amenable number.
50230432580441 is a deficient number, since it is larger than the sum of its proper divisors (1).
50230432580441 is an equidigital number, since it uses as much as digits as its factorization.
50230432580441 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 460800, while the sum is 41.
Adding to 50230432580441 its reverse (14408523403205), we get a palindrome (64638955983646).
The spelling of 50230432580441 in words is "fifty trillion, two hundred thirty billion, four hundred thirty-two million, five hundred eighty thousand, four hundred forty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •