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5024134993 is a prime number
BaseRepresentation
bin1001010110111011…
…00011011101010001
3110222010210111112211
410223131203131101
540242134304433
62150312352121
7235334304613
oct45335433521
913863714484
105024134993
112148aa1a89
12b826a5641
13620b5c157
14359384db3
151e61228cd
hex12b763751

5024134993 has 2 divisors, whose sum is σ = 5024134994. Its totient is φ = 5024134992.

The previous prime is 5024134897. The next prime is 5024135003. The reversal of 5024134993 is 3994314205.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 5019439104 + 4695889 = 70848^2 + 2167^2 .

It is a cyclic number.

It is not a de Polignac number, because 5024134993 - 213 = 5024126801 is a prime.

It is a super-2 number, since 2×50241349932 = 50483864855774220098, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (5024134393) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2512067496 + 2512067497.

It is an arithmetic number, because the mean of its divisors is an integer number (2512067497).

Almost surely, 25024134993 is an apocalyptic number.

It is an amenable number.

5024134993 is a deficient number, since it is larger than the sum of its proper divisors (1).

5024134993 is an equidigital number, since it uses as much as digits as its factorization.

5024134993 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 116640, while the sum is 40.

The square root of 5024134993 is about 70881.1328422451. The cubic root of 5024134993 is about 1712.7228820887.

The spelling of 5024134993 in words is "five billion, twenty-four million, one hundred thirty-four thousand, nine hundred ninety-three".