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5024353153 = 29799912213
BaseRepresentation
bin1001010110111100…
…11000101110000001
3110222011012120210211
410223132120232001
540242213300103
62150321154121
7235336203631
oct45336305601
913864176724
105024353153
112149130986
12b8278b941
13620c07541
143594006c1
151e616736d
hex12b798b81

5024353153 has 16 divisors (see below), whose sum is σ = 5271091200. Its totient is φ = 4782697920.

The previous prime is 5024353133. The next prime is 5024353163. The reversal of 5024353153 is 3513534205.

It is not a de Polignac number, because 5024353153 - 25 = 5024353121 is a prime.

It is a super-2 number, since 2×50243531532 = 50488249212122082818, which contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (5024353123) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2269275 + ... + 2271487.

It is an arithmetic number, because the mean of its divisors is an integer number (329443200).

Almost surely, 25024353153 is an apocalyptic number.

It is an amenable number.

5024353153 is a deficient number, since it is larger than the sum of its proper divisors (246738047).

5024353153 is a wasteful number, since it uses less digits than its factorization.

5024353153 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3312.

The product of its (nonzero) digits is 27000, while the sum is 31.

The square root of 5024353153 is about 70882.6717399958. The cubic root of 5024353153 is about 1712.7476719093.

Adding to 5024353153 its reverse (3513534205), we get a palindrome (8537887358).

The spelling of 5024353153 in words is "five billion, twenty-four million, three hundred fifty-three thousand, one hundred fifty-three".

Divisors: 1 29 79 991 2213 2291 28739 64177 78289 174827 2193083 2270381 5069983 63599407 173253557 5024353153