Base | Representation |
---|---|
bin | 10110110110011110100001… |
… | …10010101001000000100001 |
3 | 20120220212212120102200212111 |
4 | 23123033100302221000201 |
5 | 23041300131241111001 |
6 | 254512403013555321 |
7 | 13404315622554514 |
oct | 1333172062510041 |
9 | 216825776380774 |
10 | 50250325332001 |
11 | 15014052699063 |
12 | 5776a24345b41 |
13 | 220677c00bcc2 |
14 | c5a1b3304d7b |
15 | 5c21d62dd851 |
hex | 2db3d0ca9021 |
50250325332001 has 2 divisors, whose sum is σ = 50250325332002. Its totient is φ = 50250325332000.
The previous prime is 50250325331951. The next prime is 50250325332013. The reversal of 50250325332001 is 10023352305205.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 39706822782225 + 10543502549776 = 6301335^2 + 3247076^2 .
It is a cyclic number.
It is not a de Polignac number, because 50250325332001 - 239 = 49700569518113 is a prime.
It is not a weakly prime, because it can be changed into another prime (50250325332071) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25125162666000 + 25125162666001.
It is an arithmetic number, because the mean of its divisors is an integer number (25125162666001).
Almost surely, 250250325332001 is an apocalyptic number.
It is an amenable number.
50250325332001 is a deficient number, since it is larger than the sum of its proper divisors (1).
50250325332001 is an equidigital number, since it uses as much as digits as its factorization.
50250325332001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 27000, while the sum is 31.
Adding to 50250325332001 its reverse (10023352305205), we get a palindrome (60273677637206).
The spelling of 50250325332001 in words is "fifty trillion, two hundred fifty billion, three hundred twenty-five million, three hundred thirty-two thousand, one".
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