Base | Representation |
---|---|
bin | 10110110110100111101101… |
… | …00111110101001111110011 |
3 | 20120221100121010110210010122 |
4 | 23123103312213311033303 |
5 | 23041340230240000201 |
6 | 254514540113520455 |
7 | 13404552032213543 |
oct | 1333236647651763 |
9 | 216840533423118 |
10 | 50255255000051 |
11 | 15016152328692 |
12 | 577797b27312b |
13 | 2207086413c4a |
14 | c5a51dcd9323 |
15 | 5c23c3ea0e1b |
hex | 2db4f69f53f3 |
50255255000051 has 2 divisors, whose sum is σ = 50255255000052. Its totient is φ = 50255255000050.
The previous prime is 50255255000033. The next prime is 50255255000063. The reversal of 50255255000051 is 15000055255205.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 50255255000051 - 230 = 50254181258227 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 50255254999975 and 50255255000020.
It is not a weakly prime, because it can be changed into another prime (50255255000351) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25127627500025 + 25127627500026.
It is an arithmetic number, because the mean of its divisors is an integer number (25127627500026).
Almost surely, 250255255000051 is an apocalyptic number.
50255255000051 is a deficient number, since it is larger than the sum of its proper divisors (1).
50255255000051 is an equidigital number, since it uses as much as digits as its factorization.
50255255000051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 62500, while the sum is 35.
The spelling of 50255255000051 in words is "fifty trillion, two hundred fifty-five billion, two hundred fifty-five million, fifty-one", and thus it is an aban number.
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