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5029238455697 = 38923129209939
BaseRepresentation
bin100100100101111010111…
…1110001011110110010001
3122210210100021102120101202
41021023311332023312101
51124344340021040242
614410222242040545
71026231134351201
oct111136576136621
918723307376352
105029238455697
111669984aa6035
12692849949155
132a634174c121
141355b89d6401
158ac4e56c932
hex492f5f8bd91

5029238455697 has 4 divisors (see below), whose sum is σ = 5029367704560. Its totient is φ = 5029109206836.

The previous prime is 5029238455669. The next prime is 5029238455699. The reversal of 5029238455697 is 7965548329205.

5029238455697 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 5029238455697 - 216 = 5029238390161 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (5029238455699) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 64566047 + ... + 64643892.

It is an arithmetic number, because the mean of its divisors is an integer number (1257341926140).

Almost surely, 25029238455697 is an apocalyptic number.

It is an amenable number.

5029238455697 is a deficient number, since it is larger than the sum of its proper divisors (129248863).

5029238455697 is a wasteful number, since it uses less digits than its factorization.

5029238455697 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 129248862.

The product of its (nonzero) digits is 163296000, while the sum is 65.

The spelling of 5029238455697 in words is "five trillion, twenty-nine billion, two hundred thirty-eight million, four hundred fifty-five thousand, six hundred ninety-seven".

Divisors: 1 38923 129209939 5029238455697