Base | Representation |
---|---|
bin | 1110101001000000110… |
… | …11011101101100010011 |
3 | 1210002110210012012011121 |
4 | 13110200123131230103 |
5 | 31220224120302201 |
6 | 1023033403423111 |
7 | 51226115010403 |
oct | 7244033355423 |
9 | 1702423165147 |
10 | 503055244051 |
11 | 184387630588 |
12 | 815b4224a97 |
13 | 385901055a9 |
14 | 1a4c2cca803 |
15 | d143e8a9a1 |
hex | 75206ddb13 |
503055244051 has 2 divisors, whose sum is σ = 503055244052. Its totient is φ = 503055244050.
The previous prime is 503055244039. The next prime is 503055244061. The reversal of 503055244051 is 150442550305.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 503055244051 - 215 = 503055211283 is a prime.
It is a super-2 number, since 2×5030552440512 (a number of 24 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 503055243998 and 503055244016.
It is not a weakly prime, because it can be changed into another prime (503055244061) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 251527622025 + 251527622026.
It is an arithmetic number, because the mean of its divisors is an integer number (251527622026).
Almost surely, 2503055244051 is an apocalyptic number.
503055244051 is a deficient number, since it is larger than the sum of its proper divisors (1).
503055244051 is an equidigital number, since it uses as much as digits as its factorization.
503055244051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 60000, while the sum is 34.
Adding to 503055244051 its reverse (150442550305), we get a palindrome (653497794356).
The spelling of 503055244051 in words is "five hundred three billion, fifty-five million, two hundred forty-four thousand, fifty-one".
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