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503123000366641 is a prime number
BaseRepresentation
bin111001001100101100111001…
…1101101110001011000110001
32102222102002101221201221122111
41302121121303231301120301
51011421131401043213031
64542015303210005321
7210655302654165004
oct16231316355613061
92388362357657574
10503123000366641
111363462a2354516
1248518736a16841
13187973abb90315
148c353d6d5953b
153d275b57101b1
hex1c99673b71631

503123000366641 has 2 divisors, whose sum is σ = 503123000366642. Its totient is φ = 503123000366640.

The previous prime is 503123000366587. The next prime is 503123000366713. The reversal of 503123000366641 is 146663000321305.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 282721659720241 + 220401340646400 = 16814329^2 + 14845920^2 .

It is a cyclic number.

It is not a de Polignac number, because 503123000366641 - 215 = 503123000333873 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 503123000366594 and 503123000366603.

It is not a weakly prime, because it can be changed into another prime (503123000366941) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 251561500183320 + 251561500183321.

It is an arithmetic number, because the mean of its divisors is an integer number (251561500183321).

Almost surely, 2503123000366641 is an apocalyptic number.

It is an amenable number.

503123000366641 is a deficient number, since it is larger than the sum of its proper divisors (1).

503123000366641 is an equidigital number, since it uses as much as digits as its factorization.

503123000366641 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 233280, while the sum is 40.

Adding to 503123000366641 its reverse (146663000321305), we get a palindrome (649786000687946).

The spelling of 503123000366641 in words is "five hundred three trillion, one hundred twenty-three billion, three hundred sixty-six thousand, six hundred forty-one".