50323044000433 has 32 divisors (see below), whose sum is σ = 54869585379840. Its totient is φ = 45970765608960.

The previous prime is 50323044000409. The next prime is 50323044000457. The reversal of 50323044000433 is 33400044032305.

It is an interprime number because it is at equal distance from previous prime (50323044000409) and next prime (50323044000457).

It is a de Polignac number, because none of the positive numbers 2^k-50323044000433 is a prime.

It is a super-2 number, since 2×50323044000433² (a number of 28 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 50323044000395 and 50323044000404.

It is not an unprimeable number, because it can be changed into a prime (50323044000473) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 59620173 + ... + 60458341.

It is an arithmetic number, because the mean of its divisors is an integer number (1714674543120).

Almost surely, 2^{50323044000433} is an apocalyptic number.

It is an amenable number.

50323044000433 is a deficient number, since it is larger than the sum of its proper divisors (4546541379407).

50323044000433 is a wasteful number, since it uses less digits than its factorization.

50323044000433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 838857.

The product of its (nonzero) digits is 51840, while the sum is 31.

Adding to 50323044000433 its reverse (33400044032305), we get a palindrome (83723088032738).

The spelling of 50323044000433 in words is "fifty trillion, three hundred twenty-three billion, forty-four million, four hundred thirty-three", and thus it is an aban number.