Base | Representation |
---|---|
bin | 100100100111110010010… |
… | …1110101010011001100001 |
3 | 122211011200102211110211100 |
4 | 1021033210232222121201 |
5 | 1124431041000004103 |
6 | 14412123533505013 |
7 | 1026432324204354 |
oct | 111174456523141 |
9 | 18734612743740 |
10 | 5033244141153 |
11 | 1670650112888 |
12 | 693587342169 |
13 | 2a682c5b15c7 |
14 | 1358789ca29b |
15 | 8add60675a3 |
hex | 493e4baa661 |
5033244141153 has 6 divisors (see below), whose sum is σ = 7270241537234. Its totient is φ = 3355496094096.
The previous prime is 5033244141151. The next prime is 5033244141199. The reversal of 5033244141153 is 3511414423305.
5033244141153 is a `hidden beast` number, since 503 + 3 + 2 + 4 + 4 + 141 + 1 + 5 + 3 = 666.
It can be written as a sum of positive squares in only one way, i.e., 4246595768529 + 786648372624 = 2060727^2 + 886932^2 .
It is not a de Polignac number, because 5033244141153 - 21 = 5033244141151 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (5033244141151) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 279624674500 + ... + 279624674517.
Almost surely, 25033244141153 is an apocalyptic number.
It is an amenable number.
5033244141153 is a deficient number, since it is larger than the sum of its proper divisors (2236997396081).
5033244141153 is a wasteful number, since it uses less digits than its factorization.
5033244141153 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 559249349023 (or 559249349020 counting only the distinct ones).
The product of its (nonzero) digits is 86400, while the sum is 36.
Adding to 5033244141153 its reverse (3511414423305), we get a palindrome (8544658564458).
The spelling of 5033244141153 in words is "five trillion, thirty-three billion, two hundred forty-four million, one hundred forty-one thousand, one hundred fifty-three".
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