Base | Representation |
---|---|
bin | 10110111000111011001010… |
… | …10101111110000110001011 |
3 | 20121012220221102011001220021 |
4 | 23130131211111332012023 |
5 | 23044134344013000021 |
6 | 255015151513241311 |
7 | 13413353620466602 |
oct | 1334354525760613 |
9 | 217186842131807 |
10 | 50334422000011 |
11 | 15046788004486 |
12 | 578b194103237 |
13 | 2211691ab0516 |
14 | c602b0198a39 |
15 | 5c44a9279c41 |
hex | 2dc76557e18b |
50334422000011 has 2 divisors, whose sum is σ = 50334422000012. Its totient is φ = 50334422000010.
The previous prime is 50334421999987. The next prime is 50334422000033. The reversal of 50334422000011 is 11000022443305.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 50334422000011 - 215 = 50334421967243 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 50334422000011.
It is not a weakly prime, because it can be changed into another prime (50334422000411) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25167211000005 + 25167211000006.
It is an arithmetic number, because the mean of its divisors is an integer number (25167211000006).
Almost surely, 250334422000011 is an apocalyptic number.
50334422000011 is a deficient number, since it is larger than the sum of its proper divisors (1).
50334422000011 is an equidigital number, since it uses as much as digits as its factorization.
50334422000011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2880, while the sum is 25.
Adding to 50334422000011 its reverse (11000022443305), we get a palindrome (61334444443316).
The spelling of 50334422000011 in words is "fifty trillion, three hundred thirty-four billion, four hundred twenty-two million, eleven", and thus it is an aban number.
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