Base | Representation |
---|---|
bin | 100100101000010000000… |
… | …0101100101000101011001 |
3 | 122211021020211201120102211 |
4 | 1021100200011211011121 |
5 | 1124440110420120231 |
6 | 14412410430355121 |
7 | 1026466105666024 |
oct | 111204005450531 |
9 | 18737224646384 |
10 | 5034240004441 |
11 | 167101127069a |
12 | 69380495baa1 |
13 | 2a695aa0091b |
14 | 135930d7c1bb |
15 | 8ae436cceb1 |
hex | 49420165159 |
5034240004441 has 4 divisors (see below), whose sum is σ = 5072669317584. Its totient is φ = 4995810691300.
The previous prime is 5034240004429. The next prime is 5034240004499. The reversal of 5034240004441 is 1444000424305.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 5034240004441 - 227 = 5034105786713 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (5034240004741) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 19214656375 + ... + 19214656636.
It is an arithmetic number, because the mean of its divisors is an integer number (1268167329396).
Almost surely, 25034240004441 is an apocalyptic number.
It is an amenable number.
5034240004441 is a deficient number, since it is larger than the sum of its proper divisors (38429313143).
5034240004441 is a wasteful number, since it uses less digits than its factorization.
5034240004441 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 38429313142.
The product of its (nonzero) digits is 30720, while the sum is 31.
Adding to 5034240004441 its reverse (1444000424305), we get a palindrome (6478240428746).
The spelling of 5034240004441 in words is "five trillion, thirty-four billion, two hundred forty million, four thousand, four hundred forty-one".
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