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5034311301291 = 31678103767097
BaseRepresentation
bin100100101000010010001…
…0101100011100010101011
3122211021102210212211022220
41021100210111203202223
51124440232143120131
614412421454445123
71026500633003406
oct111204425434253
918737383784286
105034311301291
111671048538008
126938248037a3
132a696c7047cc
1413593a61ad3d
158ae49ab2e96
hex494245638ab

5034311301291 has 4 divisors (see below), whose sum is σ = 6712415068392. Its totient is φ = 3356207534192.

The previous prime is 5034311301289. The next prime is 5034311301293. The reversal of 5034311301291 is 1921031134305.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (5034311301289) and next prime (5034311301293).

It is a cyclic number.

It is not a de Polignac number, because 5034311301291 - 21 = 5034311301289 is a prime.

It is not an unprimeable number, because it can be changed into a prime (5034311301293) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 839051883546 + ... + 839051883551.

It is an arithmetic number, because the mean of its divisors is an integer number (1678103767098).

Almost surely, 25034311301291 is an apocalyptic number.

5034311301291 is a deficient number, since it is larger than the sum of its proper divisors (1678103767101).

5034311301291 is a wasteful number, since it uses less digits than its factorization.

5034311301291 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1678103767100.

The product of its (nonzero) digits is 9720, while the sum is 33.

Adding to 5034311301291 its reverse (1921031134305), we get a palindrome (6955342435596).

The spelling of 5034311301291 in words is "five trillion, thirty-four billion, three hundred eleven million, three hundred one thousand, two hundred ninety-one".

Divisors: 1 3 1678103767097 5034311301291