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50343134011073 is a prime number
BaseRepresentation
bin10110111001001011011001…
…00111101001111011000001
320121020202102120100002100122
423130211230213221323001
523044310214301323243
6255023152210030025
713414112535405011
oct1334455447517301
9217222376302318
1050343134011073
111504a448785322
125790a05878315
13221244c9a9a57
14c60899245c41
155c481901b668
hex2dc96c9e9ec1

50343134011073 has 2 divisors, whose sum is σ = 50343134011074. Its totient is φ = 50343134011072.

The previous prime is 50343134010991. The next prime is 50343134011127. The reversal of 50343134011073 is 37011043134305.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 47826795838864 + 2516338172209 = 6915692^2 + 1586297^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-50343134011073 is a prime.

It is a super-2 number, since 2×503431340110732 (a number of 28 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (50343134014073) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25171567005536 + 25171567005537.

It is an arithmetic number, because the mean of its divisors is an integer number (25171567005537).

Almost surely, 250343134011073 is an apocalyptic number.

It is an amenable number.

50343134011073 is a deficient number, since it is larger than the sum of its proper divisors (1).

50343134011073 is an equidigital number, since it uses as much as digits as its factorization.

50343134011073 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 45360, while the sum is 35.

Adding to 50343134011073 its reverse (37011043134305), we get a palindrome (87354177145378).

The spelling of 50343134011073 in words is "fifty trillion, three hundred forty-three billion, one hundred thirty-four million, eleven thousand, seventy-three".