Base | Representation |
---|---|
bin | 100100101000010011001… |
… | …0011111100101011100011 |
3 | 122211021112010020011102012 |
4 | 1021100212103330223203 |
5 | 1124440314133400103 |
6 | 14412425040543135 |
7 | 1026501514431404 |
oct | 111204623745343 |
9 | 18737463204365 |
10 | 5034344434403 |
11 | 1671065208449 |
12 | 693833921aab |
13 | 2a69765358bb |
14 | 135940ba39ab |
15 | 8ae4c95a2d8 |
hex | 494264fcae3 |
5034344434403 has 2 divisors, whose sum is σ = 5034344434404. Its totient is φ = 5034344434402.
The previous prime is 5034344434387. The next prime is 5034344434409. The reversal of 5034344434403 is 3044344434305.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5034344434403 - 24 = 5034344434387 is a prime.
It is not a weakly prime, because it can be changed into another prime (5034344434409) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2517172217201 + 2517172217202.
It is an arithmetic number, because the mean of its divisors is an integer number (2517172217202).
Almost surely, 25034344434403 is an apocalyptic number.
5034344434403 is a deficient number, since it is larger than the sum of its proper divisors (1).
5034344434403 is an equidigital number, since it uses as much as digits as its factorization.
5034344434403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1658880, while the sum is 41.
Adding to 5034344434403 its reverse (3044344434305), we get a palindrome (8078688868708).
The spelling of 5034344434403 in words is "five trillion, thirty-four billion, three hundred forty-four million, four hundred thirty-four thousand, four hundred three".
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