Base | Representation |
---|---|
bin | 10110111001001101110010… |
… | …10010100000000100001011 |
3 | 20121020212202012201220120001 |
4 | 23130212321102200010023 |
5 | 23044320333044430212 |
6 | 255023523555543431 |
7 | 13414156444646323 |
oct | 1334467122400413 |
9 | 217225665656501 |
10 | 50344420311307 |
11 | 1504aa48875771 |
12 | 57911045bab77 |
13 | 22125c6329155 |
14 | c6097bddc283 |
15 | 5c4891e02657 |
hex | 2dc9b94a010b |
50344420311307 has 2 divisors, whose sum is σ = 50344420311308. Its totient is φ = 50344420311306.
The previous prime is 50344420311277. The next prime is 50344420311371. The reversal of 50344420311307 is 70311302444305.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 50344420311307 - 219 = 50344419787019 is a prime.
It is not a weakly prime, because it can be changed into another prime (50344420311407) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25172210155653 + 25172210155654.
It is an arithmetic number, because the mean of its divisors is an integer number (25172210155654).
Almost surely, 250344420311307 is an apocalyptic number.
50344420311307 is a deficient number, since it is larger than the sum of its proper divisors (1).
50344420311307 is an equidigital number, since it uses as much as digits as its factorization.
50344420311307 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 120960, while the sum is 37.
The spelling of 50344420311307 in words is "fifty trillion, three hundred forty-four billion, four hundred twenty million, three hundred eleven thousand, three hundred seven".
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