Base | Representation |
---|---|
bin | 100100101000010111110… |
… | …0111101110011110011011 |
3 | 122211021221000002220121022 |
4 | 1021100233213232132123 |
5 | 1124441124124122133 |
6 | 14412452340233055 |
7 | 1026505422066545 |
oct | 111205747563633 |
9 | 18737830086538 |
10 | 5034500614043 |
11 | 167113539052a |
12 | 69387809b78b |
13 | 2a699c9b94a4 |
14 | 13595781a695 |
15 | 8ae5b50a998 |
hex | 4942f9ee79b |
5034500614043 has 2 divisors, whose sum is σ = 5034500614044. Its totient is φ = 5034500614042.
The previous prime is 5034500613971. The next prime is 5034500614093. The reversal of 5034500614043 is 3404160054305.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5034500614043 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5034500613994 and 5034500614012.
It is not a weakly prime, because it can be changed into another prime (5034500614093) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2517250307021 + 2517250307022.
It is an arithmetic number, because the mean of its divisors is an integer number (2517250307022).
Almost surely, 25034500614043 is an apocalyptic number.
5034500614043 is a deficient number, since it is larger than the sum of its proper divisors (1).
5034500614043 is an equidigital number, since it uses as much as digits as its factorization.
5034500614043 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 86400, while the sum is 35.
Adding to 5034500614043 its reverse (3404160054305), we get a palindrome (8438660668348).
The spelling of 5034500614043 in words is "five trillion, thirty-four billion, five hundred million, six hundred fourteen thousand, forty-three".
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