Base | Representation |
---|---|
bin | 101110111000110010… |
… | …111111010000111011 |
3 | 11210221122000201022102 |
4 | 232320302333100323 |
5 | 1311101310424311 |
6 | 35043404214015 |
7 | 3431411363303 |
oct | 567062772073 |
9 | 153848021272 |
10 | 50345014331 |
11 | 1a3954a2467 |
12 | 991053a30b |
13 | 499439b811 |
14 | 26184a0603 |
15 | 1499ce643b |
hex | bb8cbf43b |
50345014331 has 4 divisors (see below), whose sum is σ = 51705690432. Its totient is φ = 48984338232.
The previous prime is 50345014319. The next prime is 50345014373. The reversal of 50345014331 is 13341054305.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 50345014331 - 214 = 50344997947 is a prime.
It is a super-2 number, since 2×503450143312 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 50345014294 and 50345014303.
It is not an unprimeable number, because it can be changed into a prime (50345014231) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 680337995 + ... + 680338068.
It is an arithmetic number, because the mean of its divisors is an integer number (12926422608).
Almost surely, 250345014331 is an apocalyptic number.
50345014331 is a deficient number, since it is larger than the sum of its proper divisors (1360676101).
50345014331 is a wasteful number, since it uses less digits than its factorization.
50345014331 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1360676100.
The product of its (nonzero) digits is 10800, while the sum is 29.
Adding to 50345014331 its reverse (13341054305), we get a palindrome (63686068636).
The spelling of 50345014331 in words is "fifty billion, three hundred forty-five million, fourteen thousand, three hundred thirty-one".
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