Base | Representation |
---|---|
bin | 10110111001001111010101… |
… | …10000010001101010111011 |
3 | 20121020221220001022122011121 |
4 | 23130213222300101222323 |
5 | 23044324033022402001 |
6 | 255024142203210111 |
7 | 13414216142616526 |
oct | 1334475260215273 |
9 | 217227801278147 |
10 | 50345250200251 |
11 | 150503342705a6 |
12 | 57912b6516937 |
13 | 22126c92455b6 |
14 | c60a1a307bbd |
15 | 5c48debd06a1 |
hex | 2dc9eac11abb |
50345250200251 has 4 divisors (see below), whose sum is σ = 50345264884752. Its totient is φ = 50345235515752.
The previous prime is 50345250200239. The next prime is 50345250200281. The reversal of 50345250200251 is 15200205254305.
It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.
It is a cyclic number.
It is not a de Polignac number, because 50345250200251 - 27 = 50345250200123 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (50345250200281) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 839586 + ... + 10069528.
It is an arithmetic number, because the mean of its divisors is an integer number (12586316221188).
Almost surely, 250345250200251 is an apocalyptic number.
50345250200251 is a deficient number, since it is larger than the sum of its proper divisors (14684501).
50345250200251 is an equidigital number, since it uses as much as digits as its factorization.
50345250200251 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 14684500.
The product of its (nonzero) digits is 60000, while the sum is 34.
Adding to 50345250200251 its reverse (15200205254305), we get a palindrome (65545455454556).
The spelling of 50345250200251 in words is "fifty trillion, three hundred forty-five billion, two hundred fifty million, two hundred thousand, two hundred fifty-one".
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