Base | Representation |
---|---|
bin | 100100101000011001101… |
… | …1100010100101001110011 |
3 | 122211022002110202112001001 |
4 | 1021100303130110221303 |
5 | 1124441242032433210 |
6 | 14412502550422431 |
7 | 1026510131102110 |
oct | 111206334245163 |
9 | 18738073675031 |
10 | 5034564733555 |
11 | 16711685a5465 |
12 | 693895661a17 |
13 | 2a69b0079526 |
14 | 13596214b907 |
15 | 8ae61e7403a |
hex | 49433714a73 |
5034564733555 has 16 divisors (see below), whose sum is σ = 6940320778944. Its totient is φ = 3434385530880.
The previous prime is 5034564733537. The next prime is 5034564733603. The reversal of 5034564733555 is 5553374654305.
5034564733555 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 5034564733555 - 237 = 4897125780083 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5034564733496 and 5034564733505.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 372647926 + ... + 372661435.
It is an arithmetic number, because the mean of its divisors is an integer number (433770048684).
Almost surely, 25034564733555 is an apocalyptic number.
5034564733555 is a deficient number, since it is larger than the sum of its proper divisors (1905756045389).
5034564733555 is a wasteful number, since it uses less digits than its factorization.
5034564733555 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 745309566.
The product of its (nonzero) digits is 56700000, while the sum is 55.
The spelling of 5034564733555 in words is "five trillion, thirty-four billion, five hundred sixty-four million, seven hundred thirty-three thousand, five hundred fifty-five".
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