Base | Representation |
---|---|
bin | 100100101000101111111… |
… | …1111010110110111010001 |
3 | 122211101000120002102211222 |
4 | 1021101133333112313101 |
5 | 1124444304400141103 |
6 | 14413105045414425 |
7 | 1026534504534155 |
oct | 111213777266721 |
9 | 18741016072758 |
10 | 5035312115153 |
11 | 1671511467301 |
12 | 693a63a0a415 |
13 | 2a6a9bb68268 |
14 | 1359d34db065 |
15 | 8aea78a5638 |
hex | 4945ffd6dd1 |
5035312115153 has 2 divisors, whose sum is σ = 5035312115154. Its totient is φ = 5035312115152.
The previous prime is 5035312115111. The next prime is 5035312115191. The reversal of 5035312115153 is 3515112135305.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 4203881813569 + 831430301584 = 2050337^2 + 911828^2 .
It is a cyclic number.
It is not a de Polignac number, because 5035312115153 - 26 = 5035312115089 is a prime.
It is not a weakly prime, because it can be changed into another prime (5035312115753) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2517656057576 + 2517656057577.
It is an arithmetic number, because the mean of its divisors is an integer number (2517656057577).
Almost surely, 25035312115153 is an apocalyptic number.
It is an amenable number.
5035312115153 is a deficient number, since it is larger than the sum of its proper divisors (1).
5035312115153 is an equidigital number, since it uses as much as digits as its factorization.
5035312115153 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 33750, while the sum is 35.
The spelling of 5035312115153 in words is "five trillion, thirty-five billion, three hundred twelve million, one hundred fifteen thousand, one hundred fifty-three".
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