Base | Representation |
---|---|
bin | 100100101000110000111… |
… | …0110010111000011110011 |
3 | 122211101002201210100122002 |
4 | 1021101201312113003303 |
5 | 1124444340341423331 |
6 | 14413112122204215 |
7 | 1026535333643342 |
oct | 111214166270363 |
9 | 18741081710562 |
10 | 5035343311091 |
11 | 1671528034275 |
12 | 693a7235366b |
13 | 2a6aa546b6b2 |
14 | 1359d76dbb59 |
15 | 8aeaa4b89cb |
hex | 49461d970f3 |
5035343311091 has 2 divisors, whose sum is σ = 5035343311092. Its totient is φ = 5035343311090.
The previous prime is 5035343311021. The next prime is 5035343311147. The reversal of 5035343311091 is 1901133435305.
5035343311091 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5035343311091 - 238 = 4760465404147 is a prime.
It is a super-2 number, since 2×50353433110912 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (5035343311021) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2517671655545 + 2517671655546.
It is an arithmetic number, because the mean of its divisors is an integer number (2517671655546).
Almost surely, 25035343311091 is an apocalyptic number.
5035343311091 is a deficient number, since it is larger than the sum of its proper divisors (1).
5035343311091 is an equidigital number, since it uses as much as digits as its factorization.
5035343311091 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 72900, while the sum is 38.
Adding to 5035343311091 its reverse (1901133435305), we get a palindrome (6936476746396).
The spelling of 5035343311091 in words is "five trillion, thirty-five billion, three hundred forty-three million, three hundred eleven thousand, ninety-one".
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