Base | Representation |
---|---|
bin | 100100101000110011010… |
… | …1110111001100000011001 |
3 | 122211101022102221211111100 |
4 | 1021101212232321200121 |
5 | 1130000022330203423 |
6 | 14413124210222013 |
7 | 1026540350225361 |
oct | 111214656714031 |
9 | 18741272854440 |
10 | 5035425241113 |
11 | 167156a303533 |
12 | 693a95884909 |
13 | 2a6ab94263b7 |
14 | 135a045479a1 |
15 | 8aeb279e343 |
hex | 49466bb9819 |
5035425241113 has 12 divisors (see below), whose sum is σ = 7273412190720. Its totient is φ = 3356940848856.
The previous prime is 5035425241111. The next prime is 5035425241117. The reversal of 5035425241113 is 3111425245305.
5035425241113 is a `hidden beast` number, since 5 + 0 + 354 + 252 + 41 + 1 + 13 = 666.
It is not a de Polignac number, because 5035425241113 - 21 = 5035425241111 is a prime.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (5035425241111) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 4633528 + ... + 5616086.
It is an arithmetic number, because the mean of its divisors is an integer number (606117682560).
Almost surely, 25035425241113 is an apocalyptic number.
It is an amenable number.
5035425241113 is a deficient number, since it is larger than the sum of its proper divisors (2237986949607).
5035425241113 is a wasteful number, since it uses less digits than its factorization.
5035425241113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1551988 (or 1551985 counting only the distinct ones).
The product of its (nonzero) digits is 72000, while the sum is 36.
The spelling of 5035425241113 in words is "five trillion, thirty-five billion, four hundred twenty-five million, two hundred forty-one thousand, one hundred thirteen".
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