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50401041 = 325765371
BaseRepresentation
bin1100000001000…
…0111100010001
310111211122020020
43000100330101
5100400313131
65000134053
71151254545
oct300207421
9114748206
1050401041
11264a5059
1214a67329
13a598b02
14699da25
154658996
hex3010f11

50401041 has 8 divisors (see below), whose sum is σ = 67463904. Its totient is φ = 33469440.

The previous prime is 50401033. The next prime is 50401049. The reversal of 50401041 is 14010405.

It is an interprime number because it is at equal distance from previous prime (50401033) and next prime (50401049).

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 50401041 - 23 = 50401033 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 50401041.

It is not an unprimeable number, because it can be changed into a prime (50401049) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 31915 + ... + 33456.

It is an arithmetic number, because the mean of its divisors is an integer number (8432988).

Almost surely, 250401041 is an apocalyptic number.

It is an amenable number.

50401041 is a deficient number, since it is larger than the sum of its proper divisors (17062863).

50401041 is a wasteful number, since it uses less digits than its factorization.

50401041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 65631.

The product of its (nonzero) digits is 80, while the sum is 15.

The square root of 50401041 is about 7099.3690564726. The cubic root of 50401041 is about 369.3854932444.

Adding to 50401041 its reverse (14010405), we get a palindrome (64411446).

The spelling of 50401041 in words is "fifty million, four hundred one thousand, forty-one".

Divisors: 1 3 257 771 65371 196113 16800347 50401041