Base | Representation |
---|---|
bin | 1001011000111110… |
… | …11010110111000011 |
3 | 111000100021201110001 |
4 | 10230133122313003 |
5 | 40311044320113 |
6 | 2152130420431 |
7 | 235634126632 |
oct | 45437326703 |
9 | 14010251401 |
10 | 5041401283 |
11 | 2157815446 |
12 | b88431717 |
13 | 6245c61a9 |
14 | 35b79b519 |
15 | 1e78d37dd |
hex | 12c7dadc3 |
5041401283 has 2 divisors, whose sum is σ = 5041401284. Its totient is φ = 5041401282.
The previous prime is 5041401241. The next prime is 5041401301. The reversal of 5041401283 is 3821041405.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5041401283 is a prime.
It is not a weakly prime, because it can be changed into another prime (5041401223) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2520700641 + 2520700642.
It is an arithmetic number, because the mean of its divisors is an integer number (2520700642).
Almost surely, 25041401283 is an apocalyptic number.
5041401283 is a deficient number, since it is larger than the sum of its proper divisors (1).
5041401283 is an equidigital number, since it uses as much as digits as its factorization.
5041401283 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3840, while the sum is 28.
The square root of 5041401283 is about 71002.8258803831. The cubic root of 5041401283 is about 1714.6826594253.
Adding to 5041401283 its reverse (3821041405), we get a palindrome (8862442688).
The spelling of 5041401283 in words is "five billion, forty-one million, four hundred one thousand, two hundred eighty-three".
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