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5041430213451 = 31680476737817
BaseRepresentation
bin100100101011100110010…
…1010000011001101001011
3122211221210221101000221020
41021113030222003031023
51130044322113312301
614420000121443523
71030142224523352
oct111271452031513
918757727330836
105041430213451
111674070a20095
126950909405a3
132a7535543478
14136013c8c999
158b214a6a436
hex495cca8334b

5041430213451 has 4 divisors (see below), whose sum is σ = 6721906951272. Its totient is φ = 3360953475632.

The previous prime is 5041430213447. The next prime is 5041430213459. The reversal of 5041430213451 is 1543120341405.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 5041430213451 - 22 = 5041430213447 is a prime.

It is not an unprimeable number, because it can be changed into a prime (5041430213459) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 840238368906 + ... + 840238368911.

It is an arithmetic number, because the mean of its divisors is an integer number (1680476737818).

Almost surely, 25041430213451 is an apocalyptic number.

5041430213451 is a deficient number, since it is larger than the sum of its proper divisors (1680476737821).

5041430213451 is a wasteful number, since it uses less digits than its factorization.

5041430213451 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1680476737820.

The product of its (nonzero) digits is 28800, while the sum is 33.

Adding to 5041430213451 its reverse (1543120341405), we get a palindrome (6584550554856).

The spelling of 5041430213451 in words is "five trillion, forty-one billion, four hundred thirty million, two hundred thirteen thousand, four hundred fifty-one".

Divisors: 1 3 1680476737817 5041430213451