Base | Representation |
---|---|
bin | 100100101011111011100… |
… | …1010010110101111001100 |
3 | 122212000122122012212020222 |
4 | 1021113313022112233030 |
5 | 1130102302142401012 |
6 | 14420154554130512 |
7 | 1030166004054224 |
oct | 111276712265714 |
9 | 18760578185228 |
10 | 5042143325132 |
11 | 16743a7505491 |
12 | 69524b720a38 |
13 | 2a761a1c3844 |
14 | 13608087b084 |
15 | 8b25747c972 |
hex | 495f7296bcc |
5042143325132 has 12 divisors (see below), whose sum is σ = 8922894087240. Its totient is φ = 2492745014496.
The previous prime is 5042143325099. The next prime is 5042143325137. The reversal of 5042143325132 is 2315233412405.
It is a super-2 number, since 2×50421433251322 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 5042143325092 and 5042143325101.
It is not an unprimeable number, because it can be changed into a prime (5042143325137) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7081661618 + ... + 7081662329.
It is an arithmetic number, because the mean of its divisors is an integer number (743574507270).
Almost surely, 25042143325132 is an apocalyptic number.
It is an amenable number.
5042143325132 is a deficient number, since it is larger than the sum of its proper divisors (3880750762108).
5042143325132 is a wasteful number, since it uses less digits than its factorization.
5042143325132 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 14163324040 (or 14163324038 counting only the distinct ones).
The product of its (nonzero) digits is 86400, while the sum is 35.
Adding to 5042143325132 its reverse (2315233412405), we get a palindrome (7357376737537).
The spelling of 5042143325132 in words is "five trillion, forty-two billion, one hundred forty-three million, three hundred twenty-five thousand, one hundred thirty-two".
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