Base | Representation |
---|---|
bin | 101110111101111111… |
… | …111110100101111011 |
3 | 11211011201021120022211 |
4 | 232331333332211323 |
5 | 1311241132234111 |
6 | 35100203155551 |
7 | 3433521344506 |
oct | 567577764573 |
9 | 154151246284 |
10 | 50432305531 |
11 | 1a42a7a3653 |
12 | 9935815bb7 |
13 | 49a94b280a |
14 | 2625d0413d |
15 | 14a27da521 |
hex | bbdffe97b |
50432305531 has 2 divisors, whose sum is σ = 50432305532. Its totient is φ = 50432305530.
The previous prime is 50432305507. The next prime is 50432305559. The reversal of 50432305531 is 13550323405.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 50432305531 - 211 = 50432303483 is a prime.
It is a super-2 number, since 2×504323055312 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 50432305493 and 50432305502.
It is not a weakly prime, because it can be changed into another prime (50432305031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25216152765 + 25216152766.
It is an arithmetic number, because the mean of its divisors is an integer number (25216152766).
Almost surely, 250432305531 is an apocalyptic number.
50432305531 is a deficient number, since it is larger than the sum of its proper divisors (1).
50432305531 is an equidigital number, since it uses as much as digits as its factorization.
50432305531 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 27000, while the sum is 31.
Adding to 50432305531 its reverse (13550323405), we get a palindrome (63982628936).
The spelling of 50432305531 in words is "fifty billion, four hundred thirty-two million, three hundred five thousand, five hundred thirty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.073 sec. • engine limits •