Base | Representation |
---|---|
bin | 100100101100011111100… |
… | …1101001010010100010001 |
3 | 122212010202212120221020111 |
4 | 1021120333031022110101 |
5 | 1130112241104121431 |
6 | 14420514532441321 |
7 | 1030240651565533 |
oct | 111307715122421 |
9 | 18763685527214 |
10 | 5043352020241 |
11 | 167496780aa67 |
12 | 695528479241 |
13 | 2a7780740952 |
14 | 1361571d1853 |
15 | 8b2c86347b1 |
hex | 4963f34a511 |
5043352020241 has 4 divisors (see below), whose sum is σ = 5043516903972. Its totient is φ = 5043187136512.
The previous prime is 5043352020199. The next prime is 5043352020293. The reversal of 5043352020241 is 1420202533405.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 4447020569616 + 596331450625 = 2108796^2 + 772225^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5043352020241 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (5043352080241) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 82395976 + ... + 82457161.
It is an arithmetic number, because the mean of its divisors is an integer number (1260879225993).
Almost surely, 25043352020241 is an apocalyptic number.
It is an amenable number.
5043352020241 is a deficient number, since it is larger than the sum of its proper divisors (164883731).
5043352020241 is a wasteful number, since it uses less digits than its factorization.
5043352020241 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 164883730.
The product of its (nonzero) digits is 28800, while the sum is 31.
Adding to 5043352020241 its reverse (1420202533405), we get a palindrome (6463554553646).
The spelling of 5043352020241 in words is "five trillion, forty-three billion, three hundred fifty-two million, twenty thousand, two hundred forty-one".
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