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50435340531 = 333315047067
BaseRepresentation
bin101110111110001011…
…100011100011110011
311211011220222202120020
4232332023203203303
51311242421344111
635100352214523
73433556215062
oct567613434363
9154156882506
1050435340531
111a431486914
12993683a443
1349aa006084
1426264941d9
1514a2bd9906
hexbbe2e38f3

50435340531 has 8 divisors (see below), whose sum is σ = 67267322304. Its totient is φ = 33613459560.

The previous prime is 50435340503. The next prime is 50435340569. The reversal of 50435340531 is 13504353405.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 50435340531 - 26 = 50435340467 is a prime.

It is a super-2 number, since 2×504353405312 (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 50435340492 and 50435340501.

It is not an unprimeable number, because it can be changed into a prime (50435340031) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2513541 + ... + 2533526.

It is an arithmetic number, because the mean of its divisors is an integer number (8408415288).

Almost surely, 250435340531 is an apocalyptic number.

50435340531 is a deficient number, since it is larger than the sum of its proper divisors (16831981773).

50435340531 is a wasteful number, since it uses less digits than its factorization.

50435340531 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5050401.

The product of its (nonzero) digits is 54000, while the sum is 33.

Adding to 50435340531 its reverse (13504353405), we get a palindrome (63939693936).

The spelling of 50435340531 in words is "fifty billion, four hundred thirty-five million, three hundred forty thousand, five hundred thirty-one".

Divisors: 1 3 3331 9993 5047067 15141201 16811780177 50435340531