Base | Representation |
---|---|
bin | 111001010110010010010010… |
… | …0011101000100111100111011 |
3 | 2110011002000101122022101110211 |
4 | 1302230210210131010330323 |
5 | 1012104222040220101024 |
6 | 4544504350201051551 |
7 | 211152414016413304 |
oct | 16254444435047473 |
9 | 2404060348271424 |
10 | 504440225550139 |
11 | 136803997658a4a |
12 | 486aba8aa86bb7 |
13 | 18861680811a18 |
14 | 8c7d07407d7ab |
15 | 3d4b9ab98d594 |
hex | 1cac924744f3b |
504440225550139 has 2 divisors, whose sum is σ = 504440225550140. Its totient is φ = 504440225550138.
The previous prime is 504440225550101. The next prime is 504440225550197. The reversal of 504440225550139 is 931055522044405.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 504440225550139 - 213 = 504440225541947 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 504440225550092 and 504440225550101.
It is not a weakly prime, because it can be changed into another prime (504440225550739) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 252220112775069 + 252220112775070.
It is an arithmetic number, because the mean of its divisors is an integer number (252220112775070).
Almost surely, 2504440225550139 is an apocalyptic number.
504440225550139 is a deficient number, since it is larger than the sum of its proper divisors (1).
504440225550139 is an equidigital number, since it uses as much as digits as its factorization.
504440225550139 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4320000, while the sum is 49.
The spelling of 504440225550139 in words is "five hundred four trillion, four hundred forty billion, two hundred twenty-five million, five hundred fifty thousand, one hundred thirty-nine".
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